Question

A body of mass 0.01 kg executes simple harmonic motion about x = 0 under the influence of a force as shown in figure. The time period of S.H.M. is
(a) 1.05 s
(b) 0.52 s
(c) 0.25 s
(d) 0.03 s

Answer 1

I think the answer is option (d)

Answer 2

Answer:

Explanation:

Mass of body = m = 0.01 kg (Given)

Simple harmonic motion executed = x = 0

Force constant by slope of graph is measured as-

k = F / x

k = [8 - (-8)] / [2 - (-2)] (As in the figure)

k = 16 / 4

= 4 N/m

Angular velocity is measured as -

ω = √(k/m)

ω = √(4/0.01)

ω = 20 m/s

Thus, the time period of SHM will be calculated as -

T = 2π / ω

T = 2×3.142 / 20

T = 0.3142 s

Therefore, time period of SHM is 0.314s