Question

A body of mass 0.01 kg executes simple harmonic motion (s.H.M.) about




x  0




under the influence of a force




shown below : the period of the s.H.M. Is

Answer 1

this is just a example

Answer 2

Hey dear,
You didn't give the graph. I'll add it with an image attachment.

◆ Answer-
T = 0.3142 s

◆ Solution-
# Given-
m = 0.01 kg

# Solution-
We are given with graph if force vs displacement. Force constant is calculated by slope of graph -
k = F / x
k = [8 - (-8)] / [2 - (-2)]
k = 16 / 4 = 4 N/m

Angular velocity is given by -
ω = √(k/m)
ω = √(4/0.01)
ω = 20 m/s

Time period of SHM -
T = 2π / ω
T = 2×3.142 / 20
T = 0.3142 s

Therefore, time period of SHM is 0.3142 s.

Hope this helps you...