Question

A body of mass 0.02 kg is fired from a gun of mass 100kg the muzzke speed of shell is 80m/s find the record speed of the gun

Answer 1

by universal law of gravitation , maua + mbub = mava + mbvb

lets take m , v , u of shell as ma , va , ua

lets take m , v , u of gun as mb , vb , ub

ma = 0.02kg

mb = 100kg

ua = ub = 0 (starts from rest)

va = 80 m/s

vb = ?

maua + mbub = mava + mbvb

(0.02*0) + (100*0) = (0.02*80) + (100*vb)

0 = 1.6 + 100vb

-1.6 = 100vb

-1.6/100 = vb

-0.016 m/s is the recoil velocity of he gun

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