A body of mass 0.1 kg falling freely under gravity takes 10seconds to reach the ground. Calculate the kinetic energy and potential energy of the body when the body has travelled for 6 sec
Answers
Answered by
0
Explanation:
total height h=0.5gt²=0.5x10x10²=500m
distance travelled in 6sec=0.5x10x6²=180m
height after traveling 6sec=500-180=320m
Potential energy=mgh=0.1x10x320=320j
Kinetic Energy=0.5x0.1x(10x6)²=180j
(U can use law of conservation of energy as well
i.e. Ki+UI=Kf+Uf)
Similar questions