Question

A body of mass 0.25 kg moving with a velocity of 12 ms–1 is stopped by applying a force of 0.6 N. The impulse of this force is

Answer 1

Here,

Force = ma = m x (v-u) /t

F = 0.25 x (0-12)t

t = -5

Impulse = Ft = 0.6 X -5 = -3Nm

Answer 2

Answer:

See the above attachment for the solution.