Question

A body of mass 0.25 kg moving with velocity 12ms-1 is stopped by applying a force of 0.6N . calculate the time taken to stop the body .also calculate the impulse of this force

Answer 1

GIVEN:

M=,25KG

U=12M/S

V=0

F=-0.6/0.25=-24M/S²

T=(V-U)/A=(0-12)/(-24)=5s

'''=F×S=0.6×5=-3Ns