Question

A body of mass 0.25 kg with moving with velocity 12 m per second is stopped by applying a force of 0.6 newton calculate the time taken to stop the body also calculate the impulse of the force

Answer 1

MASS IS 0.25 KG

INITIAL VELOCITY IS 12m/s

F = 0.6 N

We have to calculate the time. 

So here it is 

Final velocity v will be 0


F = ma = m (v-u)/t = 0.25 ×-12/ t

Since force is opposite in direction  to velocity therefore

F = -0.6 N = -3t

Hence t = 6/30 = 1/5 s = 0.2 seconds

Hope it helps

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Answer 2

Since an opposite force is acting, then there will be decrease in velocity i.e retardation hence acceleration will be negative.