Question

A body of mass 0.2kg performs linear S.H.M . lt experiences a restoring force of 0.2 N when its displacement from the mean position is 4 cm . determine i)force constant. ii) period of S.H.M​

Answer 1

$\mathfrak{\huge{\orange{\underline{\underline{AnSwEr:-}}}}}$

Actually Welcome to the Concept of the S.H.M

Here, we are given =>

m = 0.2 Kg, F = 0.2 N, x = 4 cm,

1.) We know that, F = -kx,

-k = F/x ==> -k = 0.2/4

==> k = -0.05

Force constant ==> -0.05

2.) Period of S. H. M => 1/f , f = frequency

w = root over k/m

w = 0.5 , also f = w/2π

f = 0.079 Hz

so then, T = 1/f => 1/0.079 => 12.65

hence the time period is 12.65 seconds.