Question

a body of mass 0.2kg performs linear shm. it experience a restoring force of 2N when its displacement is 5cm. find force constant, acceleration of body when its displacement from mean position is 2cm, period of shm​

Answer 1

Answer:

Here, m=2kg,k=50Nm

−1

,A=5cm=0.05m. The block exectues SHM. Its angular frequency is given by

ω=

m

k

=

2kg

50Nm

−1

=5rads

−1

.

Since the time is noted from the equilibrium position, its displacement at any time t is given by

x=Asinωt=0.05sin5tm

Explanation:

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Answer 2

x=asinwt 0.05sin 5tm

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