A body of mass 0.3 kg is subjected to a force of F
= -kx with k = 15 Nm–¹What will be its initial acceleration if it is released from a point 20 cm
away from the origin?
Answers
Answered by
2
Answer: -10 m/s^2
Explanation:
F = -kx
a = F/m = -15(x)/m = -15 × 0.2/0.3 = -10 m / s^2
Answered by
2
Answer:
10 m/s²
Explanation:
Given Required Solution
k=15 N/m a=? F=-k.x
x=20 cm=0.2 m F=-15 N/m.0.2 m
m=0.3 kg F=-3 N
F=m.a
a=F/m=-3 N/0.3 kg=-10 m/s²
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