A body of mass 0.5 kg falls from a height of 5 m. How much mechanical energy does it possess at any instant of the journey? What will be the speed of the object just before it touches the ground? (take g =10 m/s2)
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1
Answer:
25m/5
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Answered by
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Answer:
m=0.5 kg, g=10 m/s, h= 5 m.
P.E= m*g*h
Thus, P.E= 0.5*10*5
= 0.5*50
= 25 J
Explanation: Since according to the principle of conservation of energy, the total energy of a body is always constant. Thus, energy possessed at any instant= the initial potential energy.
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