Question

a body of mass 0.5 kg is resting on a frictionless surface when a force of 2000 dyne acts on it for 10 seconds then calculate the distance travelled in 10 seconds

Answer 1

F=ma
a= F/m
2000 dyne = 0.2 N
a=0.2/0.5
a=0.4 m/s^2
Use equation of kinetic,
S=ut+(att)/2
S= 0+(0.4*100)/2
S=40/2
S=20 m
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Answer 2

Answer:

The distance traveled by the body is 2m.

Explanation:

Given that,

a body of mass 0.5kg is resting(u=0) on a friction less surface when a force of 2000dyne acts on it for 10 seconds.

We are required to find the distance traveled by body in given time.

The given data is written symbolically as follows

$m=0.5kg\\F=2000dyne=2000\times10^{-5}N=0.02N\\t=10sec$

We know that force is the product of mass of a body and its acceleration.Hence,

$0.02=0.5a= > a=\frac{0.02}{0.5}=0.04m/s^{2}$

The kinematic equation of motion to find distance is

$s=ut+\frac{1}{2}at^{2}$

Substituting the given values we get

$s=0+\frac{1}{2}(0.04)(10^{2})=2m$

Therefore,

The distance traveled by the body is 2m.

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