Question

a body of mass 0.5 kg is taken to height are above the Earth's surface where R is the radius of the Earth if the body is not raised to a height of 2 meters what is the increase in its potential energy

Answer 1

Answer:

Hey mate here is your answer.....

..Few assumptions,

Mass of earth = M

Universal gravitation constant = G

Radius of earth = R

So assuming in the initial state, body of mass ‘m’ is at the surface of earth

P.E1=−(G∗M∗m)/RP.E1=−(G∗M∗m)/R

When body is move to a height ‘h’

P.E2=−(G∗M∗m)/(R+h)P.E2=−(G∗M∗m)/(R+h)

(-ve sign is because there is attraction force)

So change in potential energy is

= P.E2 - P.E1

=−(G∗M∗m)/(R+h)+(G∗M∗m)/R=−(G∗M∗m)/(R+h)+(G∗M∗m)/R

=(G∗M∗m)(1/R)−(1/(R+R))Sinceh=R=(G∗M∗m)(1/R)−(1/(R+R))Sinceh=R

=(G∗M∗m)/(2∗R)=(G∗M∗m)/(2∗R)

hope it's helpful for you.....

Answer 2

height on ground=h=R

Increase in h= R/5 h=5R