Physics, asked by akshay3374, 7 months ago

A body of mass 0.5 kg is whirled round in a horizontal circle of radius 2m. If the speed of rotation is 4

m/s, find (i) the number of revolutions per second and (ii) the centripetal acceleration on the body.

Answers

Answered by umaimab87

0

Answer:

Number of revolutions per seconds = 2Pir=2×3.14×2=13.

Centripetal acceleration = v^2/r = 4^2/2=16/2=8.

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