Question

A body of mass 0.5 kg travel
in a straight line with velocity
v=kx where k=5/s. What is the
work done by net force
during its displatement from
x=0 to x=
2m?​

Answer 1

Explanation:

given that,

m = 0.5kg

v = kx where, k = 5 secs

Work done = force x displacement

total displacement = 2m

force = ma

force = 0.5*10, where, a = 10m/s²

force = 5N

work done = 5N x 2m

work done = 10N/m

hope it helps you