Question

A body of mass 0.5 kg travels in a straight line with velocity v=ax^3/2

Answer 1

$\mathbb{\huge{\purple{Zia\: Dilliwali}}}$

Velocity of the body is governed by the equation, v = ax3/2 and a = 5 m1/2 s-1

Initial velocity, u (at x = 0) = 0

Final velocity v (at x = 2 m) = 10√2 m/s

Work done, W = Change in kinetic energy

= (1/2) m (v2 – u2)

= (1/2) × 0.5 [ (10√2)2 – 02]

= (1/2) × 0.5 × 10 × 10 × 2

= 50 J