A body of mass 0.5 Kg undergoes a change of velocity of 4cm/s in 4s What is the force acting on it?
Answers
Answered by
0
As we Know That :
F=m*v/t
=0.5*4/4
=0.5 Kgm/s^2
Hence the force acting on it is 0.5 N
F=m*v/t
=0.5*4/4
=0.5 Kgm/s^2
Hence the force acting on it is 0.5 N
Answered by
1
Hi friend,
We all know the formula
F=ma
F=m ×v/t
F=0.5 ×4×10^-²/4
F=0.5 ×10^-²N.
Hope this helped you a little!!!!
We all know the formula
F=ma
F=m ×v/t
F=0.5 ×4×10^-²/4
F=0.5 ×10^-²N.
Hope this helped you a little!!!!
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