Question

A body of mass 0.50kg performs linear shm it's displacement from the mean position is given by x=0.1sin (pit/4)m find its potential energy kinetic energy and total energy

Answer 1

Answer:

1/2root2

Explanation:

x=0.1sin (pi/4)

m=0.5 kg

P=mgh

=0.5×10×0.1×1/root2

=5/10×1/root2

=1/2root2

K=1/2mv^2

=1/2×0.5×0^2

K= 0

Total energy=P+K

=1/2root2 + 0

=1/2root2