Question

A body of mass 0.5kg is thrown and it reaches a maximum height of 5m . The work done by the force of gravity during this vertical displacement is​

Answer 1

$\star\:\:\:\bf\large\underline\blue{Given:–}$

☛︎ Mass of the body, m = 0.5 kg

☛︎ Maximum height, h = 5 m

☛︎ Force of gravity, g = 9.8 N

$\star\:\:\:\bf\large\underline\blue{To\:find:–}$

The work done by the force of gravity during this vertical displacement = ?

$\star\:\:\:\bf\large\underline\blue{Solution:–}$

Work done by gravity = change in potential energy

= 0 – mgh

= 0 – 0.5 × 9.8 × 5 J

= – 24.5 J

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Hope it helps you mate ❤️

Answer 2

Answer:

force of gravity acting on the ball,

F=mg=0.5×10= 5N

Explanation:

displacement of the ball, S=5m

the force and the displacement are in the opposite directions. hence work done by the force of gravity on the ball is negative.

W = -FS

= -5×5

. = -25 j

hope this helps you!