Question

A body of mass 0.5kg undergoes a change in velocity of 4cm/s in 4 s . what is the force acting on it

Answer 1

in question given ;

acceleration=4cm/sec = 4/100 m/s

and

force =mass*acceleration

mass =0.5kg

and
acceleration =change/time

=4/100/4

=1/100

now

force = 5/10 X 1/100

= 1/200

=0.005

Answer 2

Answer:

F = 0.005 N

Explanation:

Given that,

Mass of the body, m = 0.5 kg

Charge in velocity, (v-u) = 4 cm/s = 0.04 m/s

Time, t = 4 s

Let F is the force acting on the body. The formula for the force is equal to the product of mass and acceleration as :

$F=m\times \dfrac{v-u}{t}$

$F=0.5\times \dfrac{0.04}{4}$

F = 0.005 N

So, the force acting on the body is 0.005 N. Hence, this is the required solution.