Question

A body of mass 1.5 kg is allowed to slide down along a quadrant circle from the horizontal position. In reaching to the bottom, it's velocity is 8 m/s. the work done in overcoming the friction is 12 joules. the radius of circle is (g=10m/s)

Answer 1

Using the conservation of energy

mgh=1/2 mv²+ 12

given mass =1.5Kg

velocity=8m/s

1.5*10*h=1/2*1.5*8²+12

15h=60

h=4m

so the radius also should be equal to 4m