Question

A body of mass 1.5 kg is allowed to slide down along a quadrant of a circle from the horizontalpos position. In reaching to the bottom, its velocity is 8 m per s .the work done in overcoming the friction is 12j. The radius of circle is....??

Answer 1

Using the conservation of energy, we have:

mgh=\frac{1}{2}mv^{2}+12

Hence, we get:

1.5\times 10\times h=\frac{1}{2}\times 1.5\times 8^{2}+12\Rightarrow 15h=60\Rightarrow h=4 m

Answer 2

radius is equal to 4 m.......................