Physics, asked by vedikachoukikar20ixm, 4 months ago

a body of mass 1.5 kg is thrown vertically upward with an initial velocity 30 m/s what will be its potential and kinetic energy at the highest point​

Answers

Answered by Anonymous
3

.

look at the pic......⊙.☉.........

pic (1) OR Pic (2)

{Please do not report if the answer is wrong, we have tried our best to give you the correct answer}

Attachments:

vedikachoukikar20ixm: correct
Anonymous: It would be better if you write it in your own words, sir.
Answered by Anonymous
1

 \bold{Answer\;:-}

• Mass of the body, m = 1.5 kg

• Initial velocity through which the body is thrown upwards, u = 30 m/s

• Kinetic energy at the highest point, KE = ½mv²

Therefore, KE = ½*1.5*(0)²

KE = 0

Now, by using the equation of motion,

v = u + at

• 0 = 30 + (- 10)(t)

• - 30 = - 10*t

t = 3 s

Another, equation of motion,

h = ut + ½gt²

h = (30)(3) + ½(-10)(3)²

• h = 90 - 45

h = 45 m

• Potential energy at the highest point, PE = ?

• PE = mgh

• PE = 1.5*(-10)*45

PE = 675 J

 \bold{Hope\;it \; helps\;!}

Similar questions