a body of mass 1.5 kg is thrown vertically upward with an initial velocity 30 m/s what will be its potential and kinetic energy at the highest point
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• Mass of the body, m = 1.5 kg
• Initial velocity through which the body is thrown upwards, u = 30 m/s
• Kinetic energy at the highest point, KE = ½mv²
Therefore, KE = ½*1.5*(0)²
• KE = 0
Now, by using the equation of motion,
• v = u + at
• 0 = 30 + (- 10)(t)
• - 30 = - 10*t
• t = 3 s
Another, equation of motion,
• h = ut + ½gt²
h = (30)(3) + ½(-10)(3)²
• h = 90 - 45
• h = 45 m
• Potential energy at the highest point, PE = ?
• PE = mgh
• PE = 1.5*(-10)*45
• PE = 675 J
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