A body of mass 1.50 kg is dropped from the 2nd floor of a building which is at a height of 12 m. What is the force acting on it during its fall ?
(g = 9.80 m/s²)
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Answered by
2
Explanation:
We know that F = mg
= 1.5 × 9.8 = 14.7 N
Answered by
2
Answer:
here formula use mgh
so,
first change kilogram in gram so 1.50×1000
so your gram is 1500
let's solve
1500×12×9.80
17000×9.80
166600m/s^2
Explanation:
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