A body of mass 1.50 kg is dropped from the 2nd floor of a building which is at a height of 12 m. What is the force acting on it during its fall? (g=9.80 m/s2
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f=ma
f=1.5×9.8
f=14.70
f=14.7N
f=1.5×9.8
f=14.70
f=14.7N
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Answer:
Mass = 64g = (64/1000) kg
g = 9.8
Since F = mg
F= 64/1000 * 9.8
Therefore F = 14.7 N
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