a body of mass 1.5Kg is thrown vertically upwards with an initial velocity of 15m/s.What will be its potential energy at the end of 2seconds?
Answers
Answered by
77
u = 15 m/s
g = -10 m/s²
t = 2s
h = ut + 0.5at²
⇒ h = 15×2 + 0.5×(-10)×2²
⇒ h = 30 - 0.5×10×4
⇒ h = 30 - 20
⇒ h = 10m
PE = mgh = 1.5×10×10 = 150J
g = -10 m/s²
t = 2s
h = ut + 0.5at²
⇒ h = 15×2 + 0.5×(-10)×2²
⇒ h = 30 - 0.5×10×4
⇒ h = 30 - 20
⇒ h = 10m
PE = mgh = 1.5×10×10 = 150J
aniketdgarud:
thanks sir actually in 9 science cbse marking scheme it was written the ans as 750J
have you written the question fully?
was there anything like "the person was standing on the top of a building of height 40m"?
Answered by
33
h = ut + 1/2at²
h = 15×2 + 0.5×(-10)×2²
= 30 - 0.5×10×4
= 10m
PE = 1.5×10×10 = 150J
PE=150J
h = 15×2 + 0.5×(-10)×2²
= 30 - 0.5×10×4
= 10m
PE = 1.5×10×10 = 150J
PE=150J
Similar questions