Question

A body of mass 1 it is kept at rest. A constant force of 6 N starts acting on it. Find the time taken by the body to move through distance of 12 m.

Answer 1

M = 1 kg
f = 6 N
S = 12 m
u = 0 m/s ( the object is at rest )

f = m * g
6 = 1 * g
g = 6 m/s^2

by Newton's second law ------->
S = ut + 1/2 * gt^2
12 = 0 * t + 1/2 * 6 * t^2
12 = 3 * t^2
12/3 = t^2
4 = t^2
t = 2 second


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Answer 2

Given :

• Initial velocity = 0
• Mass = 1 kg
• Force = 6 N
• Distance = 12 m

To find :

• Time taken to move 12 m .

Solution :

By the formula of Force :

Force = Mass × Acceleration

• Acceleration = Force / Mass

Acceleration = 6 / 1

Acceleration = 6 m/s² .

Now , by second equation of motion

• s = ut + 1/2 at²

Where

• s = Displacement
• u = initial velocity
• 1/2 = constant
• a = acceleration

12 = 0 × t + 1/2 × 6 t²

12 = 3 t²

12/3 = t²

4 = t²

t = √4

t = 2 sec

$\underline{\sf{\therefore\ The\ body\ will\ move\ 12\ m\ in\ 2\ seconds. }}$

____________________________

The equations of motion are :

1. v = u + at
2. s = ut + 1/2 at²
3. v² = u² + 2as
4. s = 1/2 ( u + v) t

Where

• v = Final velocity
• u = initial velocity
• s = displacement
• a = acceleration
• t = time