Math, asked by iswaraprasadaraowuri, 3 months ago

A body of mass 1 kg and 0.25g/cc of density is tied to the bottom of the water
container as shown in the fig find the tension in the string.​

Answers

Answered by prabhas24480
2

Consider the mass of the block be m, thus we get a mass of bucket + water is 2m. Now if we consider it as a two mass pulley, we get the net acceleration a by which the bucket is going down can be found by -

2mg - mg = 3ma

Thus we get a = g/3

Now we know that the bucket is accelerating with acceleration g/3 downwards hence to treat it as an inertial system we need to apply pseudo force upon it in upward direction. Thus we get in reference to the bucket net acceleration is 2g/3 downwards. Thus the pressure at the bottom is P + x 0.15 x 2g/3 = P + 1 kPa

Answered by BrainlyFlash156
2

\huge\underbrace\mathfrak \red{ANSWER }

Consider the mass of the block be m, thus we get a mass of bucket + water is 2m. Now if we consider it as a two mass pulley, we get the net acceleration a by which the bucket is going down can be found by -

2mg - mg = 3ma

Thus we get a = g/3

Now we know that the bucket is accelerating with acceleration g/3 downwards hence to treat it as an inertial system we need to apply pseudo force upon it in upward direction. Thus we get in reference to the bucket net acceleration is 2g/3 downwards. Thus the pressure at the bottom is P + x 0.15 x 2g/3 = P + 1 kPa

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