a body of mass 1 kg begins to move under the action of a time dependent force F=2ti+3t^2j newton. where i and j are directions along x and y axis what is power at time t .
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a=F/M
a= 2ti+3t^2j
on integrating we get velocity
V = 2*t^2/2 i+ 3 t^3/3 j
= t^2+t^3
Power = F.V ( power = w/t = F.S/t= F.V,S- displcemnt)
= 2t^3+3t^5
kvvijin77:
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Answered by
3
Answer:
a=F/M
a= 2ti+3t^2j
on integrating we get velocity
V = 2*t^2/2 i+ 3 t^3/3 j
= t^2+t^3
Power = F.V ( power = w/t = F.S/t= F.V,S- displcemnt)
= 2t^3+3t^5
Explanation:
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