A body of mass 1 kg hung from a light spring stretched it by 20 cm . The spring constant is
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Answer:
50 or 49 based on what is taken for gravity
Explanation:
F=kx
F=10 for 10 m/s^2 as gravity, and F=9.8 for 9.8 m/s^2 gravity [since force= mass * acceleration]
x (extension)= 0.2 meters SI units
;k=F/x
k= 10/0.2 for F=10 which gives 50
k=9.8/0.2 for F=9.8 which gives 49
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