A body of mass 1 kg initially at rest explodes and breaks into three fragments of masses in the ratio of 1:1:3. The two pieces of equal mass fly off perpendicular to eah other with a speed of 30m/s. What is the velocity of the heavier fragment?
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166
Masses of fragments: 1/5 * 1kg, 1/5* 1kg, 3/5 * 1kg
ie., 0.2 kg, 0.2 kg, 0.6 kg
Linear momentum of theirs:
0.2 * 30 m/s = 6 kg-m/s, 6 kg-m/s, 0.6 * v kg-m/s
The vector sum of the first two : 6√2 kg-m/s as they two linear momenta are perpendicular. This will be in North East direction, if the two pieces fly off in North and East directions respectively.
So linear momentum of the large piece is in the direction of South West direction as Linear momentum of all three pieces is 0 (as before explosion).
Velocity of the third piece = 6√2 kg-m/s / 0.6 kg = 10√2 m/s
in South West dir.
ie., 0.2 kg, 0.2 kg, 0.6 kg
Linear momentum of theirs:
0.2 * 30 m/s = 6 kg-m/s, 6 kg-m/s, 0.6 * v kg-m/s
The vector sum of the first two : 6√2 kg-m/s as they two linear momenta are perpendicular. This will be in North East direction, if the two pieces fly off in North and East directions respectively.
So linear momentum of the large piece is in the direction of South West direction as Linear momentum of all three pieces is 0 (as before explosion).
Velocity of the third piece = 6√2 kg-m/s / 0.6 kg = 10√2 m/s
in South West dir.
Answered by
61
Answer:
Explanation:
M=1
U=0
P'=p3
Attachments:
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