Physics, asked by va6nthakursaumyasha, 1 year ago

a body of mass 1 kg is allowed to fall freely under gravity. find the momentum and kinetic energy of the body 5 secs after it starts falling. take g= 10m/s^2.

Answers

Answered by SARDARshubham
151
GIVEN ;
m = 1kg
u =0
t = 5 sec
g = 10 m/s^2
v = ?


v = u+at
v = 0+10×5
v = 50 m/s

(1) momentum
= mv
= 1×50
= 50 kgm/s

(2) Kinetic energy
= 1/2 mv^2
=1/2 ×1 × 50 × 50
= 25×50
= 1250 Joule


hope this helped you .....
Answered by aryanagarwal466
0

Answer:

Momentum is 50kgm/s^{2}.

Kinetic energy is 1250J.

Explanation:

It is given that a body of mass 1 kg is allowed to fall freely under gravity.

We need to determine the momentum and kinetic energy of the body 5secs after it starts falling.

g=10m/s^{2}

m=1kg

u=0

t=5s

v=?

Using first equation of motion

v = u+at

v = 0+10*5

v=50m/s

Hence momentum is mv=1*50=50kgm/s^{2}

Now

Kinetic energy =\frac{1}{2} mv^{2}

=\frac{1}{2} 1*50*50

=1250J

#SPJ3

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