a body of mass 1 kg is allowed to fall freely under gravity. find the momentum and kinetic energy of the body 5 secs after it starts falling. take g= 10m/s^2.
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Answered by
151
GIVEN ;
m = 1kg
u =0
t = 5 sec
g = 10 m/s^2
v = ?
v = u+at
v = 0+10×5
v = 50 m/s
(1) momentum
= mv
= 1×50
= 50 kgm/s
(2) Kinetic energy
= 1/2 mv^2
=1/2 ×1 × 50 × 50
= 25×50
= 1250 Joule
hope this helped you .....
m = 1kg
u =0
t = 5 sec
g = 10 m/s^2
v = ?
v = u+at
v = 0+10×5
v = 50 m/s
(1) momentum
= mv
= 1×50
= 50 kgm/s
(2) Kinetic energy
= 1/2 mv^2
=1/2 ×1 × 50 × 50
= 25×50
= 1250 Joule
hope this helped you .....
Answered by
0
Answer:
Momentum is .
Kinetic energy is .
Explanation:
It is given that a body of mass is allowed to fall freely under gravity.
We need to determine the momentum and kinetic energy of the body secs after it starts falling.
Using first equation of motion
Hence momentum is
Now
Kinetic energy
#SPJ3
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