Physics, asked by sharvaryshirsat, 1 year ago

a body of mass 1 kg is dropped from a height of 5m on the ground

Attachments:

Answers

Answered by champion360
23
velocity with which it will reach the ground
v =  \sqrt{2gh}  \\ v =  \sqrt{2 \times 10 \times 5}  \\ v = 10
using 3 equation of motion
 {v}^{2}  =  {u}^{2}  - 2as \\ 0 = 100 - 0.04a \\  - 100 =  - 0.04a \\ so \: a = 2500
force =ma
so force=1Γ—2500=2500N
HOPE IT HELPS


Pandu1223: At last u must consider F (resistance)=m (g+a)
Answered by Pandu1223
24
I hope the answer is
2510 N
Similar questions