Question

A body of mass 1 kg is moving a speed of 10m/s on a level surface. It comes to rest after

travelling a distance of 5m. Calculate force experienced by the object.​

Answer 1

Answer:

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Answer 2

GIVEN :

• Mass of a body = 1 kg.
• Initial velocity, u = 10 m/s.
• Final velocity, v = 0 m/s.
• Distance = 5 m.

TO FIND :

• Force experienced by the object.

FORMULA :

• $\sf Retardation \: = \: \dfrac {(v-u)}{t}$
• $\sf Force \: = \: mass \: \times \: acceleration$

SOLUTION :

A body of mass 1 kg is moving with a speed of 10 m/s.

So, Object travels 10 m in 1 sec.

$\implies \sf 1 m \: = \: \dfrac {1}{10} \: sec$

$\implies \sf 5 m \: = \: \dfrac {5}{10} \: sec$

$\implies \sf t \: = \: \dfrac {1}{2} \: sec$

We know that,

$\sf Retardation \: = \: \dfrac {(v-u)}{t}$

$\implies \sf \dfrac {(10-0)}{2}$

$\implies \sf 10 \: \times \: \dfrac {2}{1}$

$\sf Retardation \: = \: 20 \: m/s$

Now,

$\sf Force \: = \: mass \: \times \: acceleration$

$\implies \sf 1 \: \times \: 20$

$\implies \sf Force \: = \: 20 \: N$

$\therefore$ The force experienced by the body is 20 N.