Question

A body of mass 1 kg is moving with velocity Vi=(i-2j-3k)m/s and after 10s velocity of the body becomes Vf=(-3i+2j-k)m/s. The magnitude of change in momentum of the body is________?

Answer 1

Hope it helps...............

Answer 2

Answer:

The magnitude of change in momentum of the body is 6 kg-m/s.

Explanation:

Given that,

Mass of body = 1 kg

Initial velocity $v_{i}=(i-2j-3k)$

Final velocity $v_{f} = (-3i+2j-k)$

Time t = 10 s

We need to calculate the magnitude of change in momentum of the body

Using formula of change in momentum

$\Delta P=mv_{f}-mv_{i}$

Where, m = mass of body

$v_{i}$= initial velocity

$v_{f}$= final velocity

Put the value into the formula

$\Delta P=1\times((-3i+2j-k)-(i-2j-3k))$

$\Delta P=(-4i+4j+2k)$

The magnitude of change in momentum

$|\Delta V|=\sqrt{(-4)^2+4^2+2^2}$

$|\Delta V|=6kg m/s$

Hence, The magnitude of change in momentum of the body is 6 kg-m/s.