Question

A body of mass 1 kg is projected from ground at an angle 30° with horizontal on a level ground at a speed 50 m/s. The magnitude of change in momentum of the body during its flight is

Answer 1

Change in momentum is nothing but m(v-u)

where

m = mass,

u = initial velocity,

v = final velocity

This is a case of projectile motion

Thus the final velocity must be zero and initial velocity 50 m/s

Therefore,

1(0-50)=-50

It is negative because of the deceleration