Question

A body of mass 1 kg is rotating on circular path of diameter 2m at the rate of rotation in 31.4 sec then calculate angular momentum and ratational kinetic energy

Answer 1

Hello dear,

◆ Answer-
L = 0.2 kgm^2/s
K.E. = 0.02 J

◆ Explanation-
# Given-
M = 1 kg
d = 2 m
r = 1 m
T = π = 31.4 s

# Solution-
Angular velocity is calculated by -
ω = 2π/T
ω = 2×3.14 / 31.4
ω = 0.2 rad/s

Moment of inertia is calculated by-
I = Mr^2
I = 1 × 1^2
I = 1 kgm^2

Angular momentum is given by-
L = Iω
L = 1 × 0.2
L = 0.2 kgm^2/s

Rotational K.E. is given by -
K.E. = 1/2 Iω^2
K.E. = 1/2 × 1 × 0.2^2
K.E. = 0.02 J

Hope it helps...