A body of mass 1 kg is thrown upwards with a velocity 20 m/s. it momentarily comes to rest after attaining a height of 18 m. how much energy is lost due to air friction?
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The initial kinetic energy of the 1 kg mass is given by
½ mv2 = ½ ×1×202 = 200 J.
The gravitational potential energy of the 1 kg mass at its maximum height is given by
Mgh = 1×10×18 = 180 J.
The energy lost due to air friction is therefore equal to 200 – 180 = 20 J.
½ mv2 = ½ ×1×202 = 200 J.
The gravitational potential energy of the 1 kg mass at its maximum height is given by
Mgh = 1×10×18 = 180 J.
The energy lost due to air friction is therefore equal to 200 – 180 = 20 J.
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