A body of mass 1 kg is thrown upwards with a velocity 20 m/s. It momentarily comes to rest after attaining a height of 18 m. How much energy is lost due to air friction? (g = 10 m/s2)
Answers
Answered by
7
Answer:
W by all forces =/_\ K.E
(W)friction + (W)gravity = 1/2×1×(20)^2
Wf + mgh =200
Wf + 1×10×18=200
Wf=20J
Answered by
1
Answer:
Loss of energy=
2
1
mv
2
−mgh=20J
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Explanation:
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