A body of mass 1 kg is thrown vertically upward from a tower of height 10 m with velocity 100m/s. Find the time taken by body to reach the ground.(g=10ms-2).
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Answer:
20.1 sec
Explanation:
mass = 1kg
mass is not necessary here
h ( of tower ) = 10 m
u = 100 m/s
g = 10 m/s²
maximum height ( Hmax ) =u² / 2g
Hmax=100×100/20
= 500 m
time taken => v=u+at
here , v = 0
therefore,
-u=-gt
minus gets cancelled...
t₁=u/g
=100/10
=10 sec
while falling freely,
total distance travelled = length of tower +Hmax
S=1/2gt² [ as u = 0 ]
510 = 1/2×10×t₂²
510 = 5t²
t₂² = 510/5
=102
t₂ = √102
= 10.1 [ approx. ]
total time taken = t₁+t₂
=10+10.1
=20.1 sec
please mark as brainliest:)
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