Question

A body of mass 1 kg is tied to a string and
revolved in a horizontal circle of radius 1 m.
Calculate the maximum number of revolutions
per minute, so that the string does not break.
Breaking tension of the string is 9.86 N.​

Answer 1

Answer:

The maximum number of resolution per minute is 30 r.p.m.

Explanation:

Given that,

Mass m= 1 kg

Radius r = 1 m

Force F = 9.86 N

Using the formula of force

F= mr\omega^2F=mrω

2

\omega^2=\dfrac{F}{mr}ω

2

=

mr

F

\omega=\sqrt{\dfrac{F}{mr}}ω=

mr

F

\omega=\sqrt{\dfrac{9.86}{1\times1}}ω=

1×1

9.86

\omega=3.14\ r/sω=3.14 r/s

Now, The number of resolutions per minute

\omega=\dfrac{2\pi N}{60}ω=

60

2πN

N=\dfrac{60\times3.14}{2\times3.14}N=

2×3.14

60×3.14

N= 30\ r.p.mN=30 r.p.m

Hence, The maximum number of resolution per minute is 30 r.p.m.