Question

A body of mass 1 kg lies on smooth inclined plane a block of mass m is given force 10

newton horizontally as shown .the magnitude of net normal reaction on the block

Answer 1

Answer:

                    The Magnitude of net normal reaction is 10√2

Explanation:

As the block is placed on the inclined plane , and 10N force is applied on it so it will have a reaction of force of FsinΦ and the resolution of gravitational force will be at 45⁰ due to inclined surface (i=e mgcosΦ)

Formula:

                          Magnitude (N)= FsinΦ+ mgcosΦ

N=10sin(45)+Mgcos(45)

 =10(√2 /2)+10(√2 /2)

  =5√2+5√2

Magnitude (N) =10√2

Diagram is attached for better under standing

Hope you find it helpful  :)

Answer 2

Answer:

10√2 N

Explanation:

It is done by resolving the forces in the direction of N, the reaction force offered by the surface.

Hope it helps.