Question

a body of mass 1 kg moves at a speed of 5 metre per second and makes head on collision with a body of mass 2.5 kg moving with a speed of 3 metre per second in the opposite direction what are the velocities of two bodies after collision given coefficient of restitution is equal to 0.5​

Answer 1

Answer:

mass'a' : 1 kg

speed a : 5 m/s

mass;2.5kg

speed b: -3m/s;

e= (v2-v1) /(u1-u2)

Explanation:

e= (v2-v1) /(u1-u2)

0.5 *(u1-u2)= v2-v1

0.5*5-(-3)=v2-v1

0.5*8=v2-v1

4=v2-v1

v2= v1+4

m1v1 +m2v2= m1u1+m2u2

v1 *1 + 2.5* v2= 1*5 +2.5*-3

v1+ 2.5v2 = 5-7.5

v1+2.5(v1 +4)= -2.5

1.25v1+ 10= -2.5

v1=-12.5/1.25

v1 = [-10m/s] = 10m/s

v2= [-6 m/s]= 6 m/s