a body of mass 1 kg moves at a speed of 5 metre per second and makes head on collision with a body of mass 2.5 kg moving with a speed of 3 metre per second in the opposite direction what are the velocities of two bodies after collision given coefficient of restitution is equal to 0.5
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Answer:
mass'a' : 1 kg
speed a : 5 m/s
mass;2.5kg
speed b: -3m/s;
e= (v2-v1) /(u1-u2)
Explanation:
e= (v2-v1) /(u1-u2)
0.5 *(u1-u2)= v2-v1
0.5*5-(-3)=v2-v1
0.5*8=v2-v1
4=v2-v1
v2= v1+4
m1v1 +m2v2= m1u1+m2u2
v1 *1 + 2.5* v2= 1*5 +2.5*-3
v1+ 2.5v2 = 5-7.5
v1+2.5(v1 +4)= -2.5
1.25v1+ 10= -2.5
v1=-12.5/1.25
v1 = [-10m/s] = 10m/s
v2= [-6 m/s]= 6 m/s
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