A body of mass 1 kg moving towards east with a
uniform speed of 2 m/s. A force of 2N is applied
to it towards north. The magnitude of the
displacement of the body, 2 s after the force is
applied, is
(0) 4m (2) 4/2m () 8m 2m
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Answer:
displacement in east= 2×2=4
displacement in north
s=ut +1/2at^2
=0×2 + 1/2 (2/1) 2^2
= 4
so net displacement =rooot( 16+16)=16root2
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