A body of mass 10 kg has a potential energy of 8000 J. what is the height of body? if the body is dropped from that height, what is the velocity with which the body hits the ground?
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P.E = mgh
h = P.E/ mg = 8000/10×10=80m
H=vi^2/2g
vi^2=H×2g
vi^2=80×2×10
vi^2=1600
taking squareroot on both sides
sqrtvi^2=sqrt 1600
vi=40m/s
h = P.E/ mg = 8000/10×10=80m
H=vi^2/2g
vi^2=H×2g
vi^2=80×2×10
vi^2=1600
taking squareroot on both sides
sqrtvi^2=sqrt 1600
vi=40m/s
that true answer ?? please
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