Question

a body of mass 10 kg initially at rest is subjected to a force of 20N. find the kinetic energy acquired by the body at the end of 10 secs..

Answer 1

mass 10 kg  , force  20N   , time 10 s     , u   0 m/s     , g  9.8m/s^2                 using v=u+gt  ,  v = 0 + 9.8 ×10 =98 m/s^2                                             kinetic energy =1/2mv^2                       =1/2 × 10 ×98 ×98=48020 Joule

Answer 2

The kinetic energy acquired by the body at the end of 10 sec is 2000 Joules.

Explanation:

Given that,

Mass of the body, m = 10 kg

Initially the body is at rest, u = 0

Force acting on the body, F = 20 N

Let v is the final speed of the body. We can find it using equation of motion as :

$v=u+at$

$v=at$ (since, F=ma)

$v=\dfrac{Ft}{m}$

$v=\dfrac{20\times 10}{10}$

v = 20 m/s

The kinetic energy of the body is given by :

$K=\dfrac{1}{2}mv^2$

$K=\dfrac{1}{2}\times 10\times (20)^2$

K = 2000 J

So, the kinetic energy acquired by the body at the end of 10 sec is 2000 Joules.

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