Question

A body of mass 10 kg is acted upon by two perpendicular forces, 6N and 8N. The resultant acceleration of the body is *



(a) 1 m s^–2 at an angle of tan-^1 (4 / 3) w.r.t. 6N force.

(b) 0.2 m s^–2 at an angle of tan-^1 (4 / 3) w.r.t. 6N force.

(c) 1 m s^–2 at an angle of tan-^1 (3 / 4) w.r.t. 6N force.

(d) 0.2 m s^–2 at an angle of tan-^1 (3 / 4) w.r.t. 8N force​

Answer 1

Answer:

a)

Explanation:

Resultant force = √(6^2 + 8^2 + 2*6*8*cos90)

                          = √(36 + 64) = 10N

Mass = 10 kg.

So, Acceleration = 1 m/s^2

Now, if the angle b/w resultant and 6N be x,

then tanx = 8*sin90/6 + 8cos90 = 8/6 = 4/3

So, x = tan^-1(4/3)