Question

a body of mass 10 kg is being acted upon by a force 3t^2 N and an opposing force 32 N. what will be the netforce acting on body after 30 s

Answer 1

Answer:

Net force on the body is F=3t

2

−32

so net acceleration will be a=

m

F

=0.3t

2

−3.2

We know that acceleration is a=

dt

dv

so dv=adt

integrating both sides we get ∫

v=10

V

dv=∫

t=0

t=5

(0.3t

2

−3.2)dt

we get the new velocity after 5s as V=10+

3

0.3

(5

3

−0)−3.2(5−0)

or V=6.5m/s