A body of mass 10 kg is hanging from another body of mass 15 kg as shown in figure. The
combination is pulled up by a string with an acceleration of 1.2 m/s2. Find the tensions (ir
N) at points A and B. (Take g = 10 m/s²)
Answers
Answered by
12
Answer:
The upper string which is eventually pulling both will have a tension TA=(10+15)×(9.8+1.2)=275N The string which is between the masses will have a tension of TB=10×(9.8+1.2)=110N
Similar questions