A body of mass 10 kg is hung by a spring balance in a lift. what would be the reading of the balance when the lift is ascending with an acceleration of 2
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Hello dear,
● Answer-
W = 120 N
● Explaination-
# Given-
a = 2 m/s^2
m = 10 kg
# Solution-
When lift is ascending apparent acceleration is given by-
a' = a + g
a' = 2 + 10
a' = 12 m/s^2
Apparent weight of the mass is calculated by-
W = ma'
W = 10 × 12
W = 120 N
Therefore, the spring balance will read the weight as 120 N.
Hope it helps...
● Answer-
W = 120 N
● Explaination-
# Given-
a = 2 m/s^2
m = 10 kg
# Solution-
When lift is ascending apparent acceleration is given by-
a' = a + g
a' = 2 + 10
a' = 12 m/s^2
Apparent weight of the mass is calculated by-
W = ma'
W = 10 × 12
W = 120 N
Therefore, the spring balance will read the weight as 120 N.
Hope it helps...
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